Difference between revisions of "HasFriendDisposition"
Jump to navigation
Jump to search
imported>Geckbot m (Robot: Automated text replacement (-\[\[Category:(.*?)Functions\]\] +Category:\1Functions\nCategory:\1Functions (GECK 1.0))) |
imported>Geckbot m (Robot: Automated text replacement (-\[\[Category:(.*?)\(GECK 1.0\)\]\] +Category:\1(GECK 1.1))) |
||
Line 26: | Line 26: | ||
[[Category:Functions]] | [[Category:Functions]] | ||
[[Category:Functions (GECK 1. | [[Category:Functions (GECK 1.1)]] | ||
[[Category:Condition Functions]] | [[Category:Condition Functions]] | ||
[[Category:Condition Functions (GECK 1. | [[Category:Condition Functions (GECK 1.1)]] |
Latest revision as of 12:40, 15 August 2009
Description[edit | edit source]
*HasFriendDisposition function returns 1 if the actor who it is called on is equal or greater to the friend disposition game setting. It is called on a Reference and takes no parameters. It is also a Condition Function.
Syntax[edit | edit source]
[ActorREF.]HasFriendDispostion
Examples[edit | edit source]
FreddyRef.HasFriendDispostion
Will return 1 if Freddy has the friend disposition or 0 if not.
Notes[edit | edit source]
- None at this time
See Also[edit | edit source]
CheckSpeechDispositionBoost
FriendDispositionBoost
SetDisposition
Reference[edit | edit source]
None provided.